File Upload via iControl REST Code : def _upload(host, creds, fp): chunk_size = 512 * 1024 headers = { 'Content-Type': 'application/octet-stream' } fileobj = open(fp, 'rb') filename = os.path.basenam...Show MorePublished Nov 05, 2015View ContributorsVersion 1.0
JRahmAdminApr 25, 2016ok, so change that "will not work" to "is not supported" before 12.0 :) Nice work guys.