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4 Replies

  • you create a new HTTP monitor (parent is http monitor) and provide the GET string "/ServerStatusApp/serveronline.html" and the response you expect (200 OK or any expected string). Are your pool members 172.16.36.21:7003 and 172.16.36.22:7003 ? If so, simply apply this new monitor to the pool.

     

  • Dear Amolari

    Thank you for good answer. I had check with String "GET /ServerStatusApp/serveronline.html\r\n\r\n" and it had done. But I want check with 200 OK and Body " Server Online". You can see information below: [root@F5_3900_01:Active:Changes Pending] config telnet 172.16.36.21 7003 Trying 172.16.36.21... Connected to 172.16.36.21. Escape character is '^]'. GET /ServerStatusApp/serveronline.html

    HTTP/1.1 200 OK Connection: close Date: Tue, 14 Apr 2015 03:39:38 GMT Content-Length: 284 Content-Type: text/html Last-Modified: Tue, 14 Apr 2015 02:57:42 GMT X-ORACLE-DMS-ECID: c0186227297c5397:-34d9d6a3:14cb5c53e77:-8000-0000000000002511 X-Powered-By: Servlet/2.5 JSP/2.1

    http://www.w3.or g/TR/html4/loose.dtd">

    Server Online
    

    Connection closed by foreign host. [root@F5_3900_01:Active:Changes Pending] config How do check HTTP with body information "Server Online"?

    Best regards

  • Hi, you can achieve this by creating custom page where you can hard code value "Server Online" on page & LB will compare value in receive String section.

     

  • Dear Amolari and Samir I had successed monitor HTTP services via Link check. Thank you very much for your support.

     

    Best Regards